Potential Hydraulic Head from Water yield

Science, Research & Data
1

Hello,

Can I use my annual water yield output raster with other parameters using darcy velocity to get the potential hydraulic head per pixel of my study area?

Thank you

2

Hello,

Can I use my annual water yield output raster with other parameters using darcy velocity to get the potential hydraulic head per pixel of my study area?

Thank you

3

Interesting question! I’ll see if one of our hydrologists might be able to answer this.

James

1 Like
4

Respected @jdouglass,

I would really appreciate it if I could find a solution here.

Thank you

5

Along_River_2023-12-08 193533
Along_River_2023-12-08 193533906Γ—688 18.4 KB

ROR_Hydraulic_Head
ROR_Hydraulic_Head863Γ—678 49.5 KB

I got this using an empirical formula with an Annual water yield raster in GIS, but I’m unsure. Still, I would want to validate it with another watershed with a hydropower project before adopting it for my watershed. The above-uploaded files are the calculated hydropower potential along the river and the hydraulic head of the entire watershed.

6

Sounds interesting! In case anyone is interested in this topic in the future, what empirical formula did you apply?

Most of our scientific staff are busy preparing for the American Geophysical Union’s annual meeting next week, so I anticipate they may be able to respond afterwards.

James

7

𝑄= (π‘Šπ‘Žπ‘‘π‘’π‘Ÿ π‘Œπ‘–π‘’π‘™π‘‘ raster/1000) ×𝐢𝑒𝑙𝑙 π΄π‘Ÿπ‘’π‘Ž
π‘‰π‘’π‘™π‘œπ‘π‘–π‘‘π‘¦ (𝑉) = ((π‘Šπ‘Žπ‘‘π‘’π‘Ÿ π‘Œπ‘–π‘’π‘™π‘‘ raster/1000) ×𝐢𝑒𝑙𝑙 π΄π‘Ÿπ‘’π‘Ž )/(π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ π‘‘β„Žπ‘’ π‘€π‘Žπ‘‘π‘’π‘Ÿβ„Žπ‘’π‘‘)
Darcy law and Velocity equation, Q=Q
𝑖=𝑉/𝐾
Therefore, Head = 𝑖 Γ— π‘™π‘’π‘›π‘”π‘‘β„Ž of flow

I need more contributions

1 Like
8

Respected @jdouglass,

I will await the response of the scientific staff after the AGU annual meeting. Thank you always